Question

Find the critical value of t for a 98​% confidence interval with df equals = 19.

1. t = [ ]? Round to two decimals as needed

Answer 1

Solution :

Given that,

Degrees of freedom = df = 19

At 98% confidence level

$\alpha$ = 1 - 98%

$\alpha$ =1 - 0.98 =0.02

$\alpha$/2 = 0.01

t$\alpha$/2,df = t_{0.01, 19} = 2.54

critical value = 2.54