Question

Part A When titrated with a 0.1198 M solution of sodium hydroxide, a 58.00 mL solution of an unknown polyprotic acid required

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Part A : molar concentration of unknown acid = 0.04162 M

Part B : volume of NaOH required = 60.45 mL

Explanation

Part A :

concentration NaOH = 0.1198 M

volume NaOH = 20.15 mL

moles NaOH = (concentration NaOH) * (volume NaOH)

moles NaOH = (0.1198 M) * (20.15 mL)

moles NaOH = 2.414 mmol

moles acid present = 2.414 mmol

concentration of acid = (moles acid present) / (volume of acid)

concentration of acid = (2.414 mmol) / (58.00 mL)

concentration of acid = 0.04162 M

Add a comment
Know the answer?
Add Answer to:
Part A When titrated with a 0.1198 M solution of sodium hydroxide, a 58.00 mL solution...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Part A When titrated with a 0.1038 M solution of sodium hydroxide, a 52.00 mL solution...

    Part A When titrated with a 0.1038 M solution of sodium hydroxide, a 52.00 mL solution of an unknown polyprotic acid required 22.86 mL to reach the first equivalence point. Calculate the molar concentration of the unknown acid. VALDO ? Submit Request Answer

  • If 25 mL of nitric acid is titrated with 0.12 M sodium hydroxide and it took...

    If 25 mL of nitric acid is titrated with 0.12 M sodium hydroxide and it took 10 mL of the sodium hydroxide to fully neutralize the nitric acid, what was the concentration of the nitric acid at the start of the titration? D View hint for Question 19 Question 20 (4 points) How many milliliters of 2.25 M HCl would be required to titrate 6.00 g of KOH? Your Answer: Answer units

  • A 10.00 mL sample of pineapple juice was titrated with 0.100 M sodium hydroxide solution. The...

    A 10.00 mL sample of pineapple juice was titrated with 0.100 M sodium hydroxide solution. The average volume of NaOH required to reach the endpoint was 12.8 mL. a. Calculate the number of moles of sodium hydroxide required to reach the endpoint. b. Using the mole ratio(number of moles of citric acid divided by the number of moles of sodium hydroxide) for the neutralization reaction , determine the number of moles of citric acid in 10 mL of pineapple juice...

  • 2. Calculate the mass of solid sodium hydroxide needed to prepare 300 mL of 0.1 M...

    2. Calculate the mass of solid sodium hydroxide needed to prepare 300 mL of 0.1 M sodium hydroxide. Note: Be sure to include this mass in the procedure for Part C. 3. A 0.6250 g sample of KHP (204.2 g/mol), dissolved in 50 mL water, required 28.50 mL of sodium hydroxide to reach the end point. What is the concentration of the sodium hydroxide solution? 4. A 25.00 mL sample of hydrochloric acid was titrated using the same sodium hydroxide...

  • In a titration, 25 mL of 0.10 M weak diprotic acid solution was titrated by 0.10 M sodium hydroxide, NaOH, and produ...

    In a titration, 25 mL of 0.10 M weak diprotic acid solution was titrated by 0.10 M sodium hydroxide, NaOH, and produced a titration curve listed below. (20 points total) 14,0 3. 12.0 10.0 8.0 pH 6.0 4.0 2.0 10.0 5.0 20.0 30.0 15.0 25.0 Volume of 0.100 M NaOH, mL The acid used in above titration is a weak diprotic acid. Briefly explain how you know it's diprotic from looking at the titration curve and how you know a...

  • A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution....

    A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach equivalence point. In a separate titration, a 10.0 mL H3PO4 solution was titrated with the same NaOH solution. This time, 34.9 mL NaOH was required to reach the equivalence point. What is the concentration of the H3PO4 solution?

  • Consider a titration of 25.00 mL Chloroacetic Acid solution [ka=1.4x10^-3] with 0.1202 M solution of sodium...

    Consider a titration of 25.00 mL Chloroacetic Acid solution [ka=1.4x10^-3] with 0.1202 M solution of sodium hydroxide. The volume of 27.40 mL of NaOH(aq) was needed to reach the equivalence point. Calculate: a) The concentration of the chloroacetic acid solution before the titration b) the pH of the chloroacetic acid solution before titration c) the pH of the solution at half equivalence point d) the pH of the solution at the equivalence point e) the pH of the solution when...

  • Q. #11. 25.00 mL of 0.100 M HNO, acid is titrated with 0.110 M sodium hydroxide...

    Q. #11. 25.00 mL of 0.100 M HNO, acid is titrated with 0.110 M sodium hydroxide solution (a) What is the pH of the acid solution before any base solution is added? (b) What is the pH of the titration mixture after 15.00 mL of base are added? (c) What is the pH at the equivalence point/end point?

  • Consider a titration of 20.00mL cyanic acid solution (Ka=3.5x10^-4) with 0.1082 M solution of sodium hydroxide....

    Consider a titration of 20.00mL cyanic acid solution (Ka=3.5x10^-4) with 0.1082 M solution of sodium hydroxide. The volume of 21.70 mL of NaOH(aq) was needed to reach the equivalence point. Calculate: a) the concentration of the cyanic acid solution before the titration b) the pH of the cyanic acid solution before the titration c) the pH of the solution at half-equivalence point

  • When a 29,8 mL sample of a 0.322 M aqueous acetic acid solution is titrated with...

    When a 29,8 mL sample of a 0.322 M aqueous acetic acid solution is titrated with a 0,434 M aqueous sodium hydroxide solution, (1) What is the pH at the midpoint in the titration? (2) What is the pH at the equivalence point of the titration? (3) What is the pH after 33.2 mL of sodium hydroxide have been added?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT