Question

A loop of wine in shape of equilateral a lesina region where urriform mag! field of .045T in 42 direction. L= 15m for each side & current" of 072A travels, cw around loop. Hy + + Determine the magn. and, dir of the magnetic moment of Current loop a + + Som

Answer 1

magnetic moment(M) of current carrying loop is given by,

$M=NIA$

N is number of turns

I is current in the loop

A is area of loop perpendicular to magnetic field.

Here, N=1

I=0.072A

area of equilateral triangle=$\frac{\sqrt{3}}{4}a^2=\frac{\sqrt{3}}{4}*(0.15)^2m^2=9.7425*10^{-3}m^2$

So,

$M=(1)*(0.072A)*(9.7425*10^{-3}m^2)=7.0146*10^{-4}Am^2$