Ans 1 :
Number of mol of phosphorus = mass / molar mass
= 3.45 g / 30.97 g/mol = 0.111 mol
Mol chlorine = 19.75 g / 35.453 g/mol = 0.557 mol
dividing the number of moles by a common value we get the ratio of number of moles as 1 : 5
so the empirical formula of compound will be : PCl5
1. A sample of a compound is found to contain only 3.45g of phosphorus and 19.75g...
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An organic compound X was found to contain only C, H, and Cl. The following experiments were carried out with compound X: 1) When a 1.50-g sample of the compound was completely combusted in air, 3.52 g CO2 was formed. 2) When a 1.00-g sample of the compound was allowed to react with an excess of Ag, 1.27 g of AgCl was obtained. Determine the empirical formula of compound X. A0.258-g sample of a pure triprotic acid,...
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