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ne that you are doing an experiment in order to determine the mass of an object t us say that as a result of the experiment, you determine that the best approximation of the mass is 83.45 g with a standard uncertainty of 0.34 g Et is sometimes convenient to write the result as 83.45t 0.34 g. The result 83.45 g0.34 g defines an interval on the number line (between 83,.11g to be f 79 g) in which we can expect a (large) fraction of the possible values of the mass (Remember that we can never know the true value of the mass.) ound. 83.00 83.10 83.20 83.30 83.40 83.50 83.60 83.70 83.80 83.90 grams What fraction of the possible values of the mass lie between 83.11 g and 83.79 g? Another way of asking this question is How confident are you that the value of the mass lies between 83.11 g and 83.79 g? Remember that the standard uncertainty is related to the averoge width of the pof that you are using (see Appendix G for more details). The area of the pdf within the average width is about 68% of the total area of the pdf. (This is not strictly true, as it does depend of the particular pdf being used, although we dont make a distinction here.) p(m) Area- 0.68 m (g) 83.45+0.34g The shaded area in the pdf above is the area within one standard approximation. We call this area, expressed as a percentage, the coverage probability (or level of confidence). uncertainty of the best
The coverage probability is a measure of the probability that the value of the measurand lies between y- u and y+u, where y is the best uncertainty. Remember that you are 100% sure that the value of the measurand lies somewhere under the interval spanned by the entire pdf, since the area under the whole pdf approximation and u is the standard is always unity Therefore when you state the result of a measurement as the best approximation of the mass is 83.45 g with a standard uncertainty of 0.34 g. you understand that there is a 68% probability that the value of the mass exists somewhere within the interval 83.45 0.34 g, with the most likely value (the best approximation of the measurand) being 83.45 g Remember that there is a 32% probability that the measurand may exist outside of the interval 83.45t 0.34 g Now consider the two situations below. Two independent experiments were completed in order to determine the mass m of an object. The final results of the two experiments are shown below as Gaussian pdfs which are used to describe all available information about the measurand in each case. Experiment A Experiment B p(m) Area 0.68 Area 0.68 m (g) m (g) 83.50 0.12 g 83.50+0.06 g From these pdfs it can be seen that both results have 83.50 g for the best approximation of m, but measurement A has m) 0.12 g and measurement 8 has m)- 0.06 g Which one of the two measurements do you think is the best and why? Do not proceed to the next page until you have completely answered the questions on this page.
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