Question

What is the molarity of an HCl solution il 25.5 mL of a 0.46 M NaOll solution are needed to neutralize 18.0 mL of the sample? MHCI

Answer 1

Number of moles of NaOH = molarity * volume of solution in L

Number of moles of NaOH = 0.46 * 0.0255 = 0.0117 mole

From the balanced equation we can say that

1 mole of NaOH requires 1 mole of HCl so

0.0117 mole of NaOH will require

= 0.0117 mole of NaOH *(1 mole of HCl / 1 mole of NaOH)

= 0.0117 mole of HCl

molarity of HCl = number of moles of HCl / volume of solution in L

molarity of HCl = 0.0117 / 0.018 = 0.650 M

Therefore, the molarity of HCl = 0.650 M