Question

A brick is thrown upward from the top of a building at an angle of 25° to the horizontal and with an initial speed of 15 m/s. The brick hits the ground after 3.0 s of flight 1 a. Calculate the height of the building. [Label all kinematics charts clearly.] b. Suggest what kind of building this might be, and whether this brick was thrown by hand or with a brick cannon. Justify your answer as you would to a non-physicist c. State the magnitude and direction of the brick's velocity and acceleration vectors at the instant after the brick was released. Justify your answers. Velocity: Magnitude Direction Acceleration: Magnitude Direction d. State the magnitude and direction of the brick's velocity and acceleration vectors at the instant immediately before the brick hit the ground. Justify your answers. Velocity: Magnitude Direction Acceleration: Magnitude Direction

Answer 1

D O -25° u= 15 mis t - 3 sec (6) 4 =-using)t + I gte H=(-15 Sin 25) (3) +4 +9.8) (3) - -19 + 44.1 - 5.1m Height of building. 6) It would not be a building made up of bricks as such a tall building are never reliable to made by bricks. It is thrown with brick connon because it is not possible to theom brich by hand with a velocity of 15 ml (0) Magnitude of vel = 15 m/s direction . n = 25° above horizontal magnitude of occ. = 9.8 mils? direction un = vertically downwards di mag. of vel. = slucose) + (-Ughot gje = 5184.813 + 531.797 - $26.77 mis direction = Ton! ($531797) (59.5/below Horizontal. occ. - 9.8 multe direction - vertically downwards.

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