Question

b) What is the chance that a person gets put on Facebook's list, given that they are not a terrorist? Show your work. (5 points) c) What is the chance that a person's not a terrorist, given that they are on Facebook's list? Show your work. (5 points) d) When you compare your answers to parts b & c, do you find it puzzling? Why or why not? Explain. (7 points)

please answer 4 C & D

Answer 1

4.

b.

$P(OnFblist|NotTerrorist)=\frac{99990}{99990+199890010}=0.0005$

c.

Ans:

Chance that a person is not a terrorist, given that they are on Facebook's list:

$P(NotTerrorist|On FbList)=\frac{99990}{99990+10}=\frac{99990}{100000}=0.9999$

d. When comparing, I do not find it puzzling because:

• In part b, we have probability of a person being on FB list, given that he is not terrorist. Pool of non-terrorist people is huge. In other words, it is P(not Terrorist and on Fb list) / P(On Fb list).
• In part c, we have probability of a person not being a terrorist, given that he/she is on Fb list. This time pool is smaller. In other words, it is P(not Terrorist and on Fb list) / P(not Terrorist).

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