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Answer #1

Remember:
For parallel combination
Ceq = C1 + C2 + C3 +...............
for series combination
1/Ceq = 1/C1 + 1/C2 + 1/C3 + ............
for 2 capacitors in series it will be
Ceq = C1*C2/(C1+C2)
Using this Information:

In the circuit, upper 3 capacitors are in series, So

1/Cs1 = 1/C1 + 1/C2 + 1/C3

1/Cs1 = 1/6 + 1/6 + 1/6 = 3/6

Cs1 = 6/3 = 2 uF

Similarly lower 3 are also in series, So

Cs2 = 2 uF

Now Cs1 and Cs2 are in parallel, So

Ceq = C1 + C2

Ceq = 2 + 2

Ceq = 4 uF

Correct option is C.

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