Question

 for normal distribution z score =(X-μ)/σx here mean=       μ= 24 std deviation   =σ= 0.300 sample size       =n= 100 std error=σx̅=σ/√n= 0.0300

P(declare faulty if mean is less than 23.91 or more than 24.09):

 probability = 1-P(23.91

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