Question

Two particles with masses m and 3m are moving toward each other along the x-axis with the same initial speeds v0. Particle m is traveling to the left and particle 3m is traveling to the right. They undergo an elastic, off-center/oblique collision such that m is moving downward after the collision at a right angle from its initial direction. Find the final speeds of the two particles, and the angle θ at which the particle 3m is scattered.

Answer 1

sol: the horizontal component of momint - Pix + Prix - Pafx t Paft m, a m , m₂ = 3m. i denote initial of denote final insuffix - mot 3m Vou m Virx + 33 m Vzx since palticle on use a move at go after collision Vgfxo N 2m Vo = 3 m Veto y component of momentum in Prix & Riy & Pafyt lzfy oto. -msfy + 3 m Vagy m, move downward so Upy u negative. Vify a 3 Vafy conservation of energy. using ya Vify, and by Vafy Vagy from figure 2 m Và Imbify + 23 m ( v ery) Since and Vy v

Page No. _ 1 v 2, 4 (345) + 13 (( V) - M ) وهو ما شما د اپ 480² - 12 Vory + 480² 12 Vaty - 400 - 4,2 12,7 = 8V ² 12x3 Vefy - 12 Vo foral wality hom and ify - 3 - 3x z ve 23xşve Vity - 12 vo final velocity ofm - Virx + Very (²) , (ali Vive + 2 Vo² . / ² V. a o final velocity of 3m. v

and o i o- tani Vzty - tan/Evo X tan 0 - 35.260