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Question 2 In the figure R1 = 5.72 Ω, R2 = 17.2 Ω, and the ideal battery has emf ε = 10.3 V. (a) what is the magnitude of current i? (b) How much energy is dissipated by all four resistors in 2.31 min? RI R2 R2 R2 (a) Number Units (b) Number Units

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Answer #1

for series combination of resistances-

the equivalent resistance-

R=R1+R2+R3+.....................

for parallel combination-

1/R= 1/R1+1/R2+1/R3+.................

R=[1/R1+1/R2+1/R3+.........]-1

THE ENERGY DISSIPATION ACROSS RESISTANCE(E)=i2Rt

i is current flowing through resistance(R).

2. R, 2. RSge) The enuival ent Resistanee bekwcen poin Aa 8 CRa*) AB RAR2 The equtlyalcnt Resistane of circuit R RtRAs Ri ani RAs are in senes) R = 11-45-The cuent in ircuit C3) 11.45 1145 114S 2 The au htc Resistances bckucen Point Aand arc equal 3 ca) (リ R:ㄨˊㄧ-, Total energy bissipated by au four Resistor in ーナ= 2.31 min 2-31 nin 138.6 Sec (0.9)% 5.12 E = 1640.4 Joule Ary

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