1)a) heating the solution = increases
b) stirring the solution = increases
c) Grinding the solute = increases
2)KCl will be residue ,.mass of KCl =0.613g
% mass = 0.613×100/27.913
=> 2.2 %
Molarity =0.613/74.5×0.025 => 0.329 M
3) if total mass is 100 g then mass of glucose = 10 g
Moles of Glucose = 10/180 => 0.056 mol
Volume = mass/d
= 100/1.04 => 96.2 mL = 0.0962 mL
Molarity = 0.056/0.0962
=> 0.578 M
Post-lab: What is the effect of each of the following on the rate of dissolving a...
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