Question

An ideal gas is brought through an isothermal compression process. The 2.00 moles of gas go from having an initial volume of 202.2 106 m3 to 116.9 10 m3. f 8290 J are released by the gas during this process, what are the temperature T of the gas and the final pressure p? Number Number Pa

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Answer #1

Work done in isothermal compression-

W= -nRTln(V​​​​​​f​​​​​/V​​​​​​i)

Vi =202.2x10-6m3

V​​​​​​f​​​​​= 116.9x10-6m3

Q=8290J

n=2mole

R=8.314 JK​​​-1mole​​​-1

For isothermal process

W=Q=8290=2x8.314xTxln(116.9/202.2)

T=909.88K Ans.

Gas equation PV=nRT

P​​​​​​f​​​​​ =nRT/V​​​​f =2x8.314x909.88/(116.9x10-6) =1.294x10-4 Pascal Ans.

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