22. In a sample of 300 adults, 52 smoke. (22.a) Calculate the proportion of smokers in the sample. (Show your calculations.) (22.b) When we use Excel function =CONFIDENCE.T(α,σ,n), we need the value σ. Calculate that σ in this problem. (Show your calculations.) (22.c) Figure out the value E by using Excel function =CONFIDENCE.T(α,σ,n), with allowed error rate 0.05. (22.d) What is the 95% confidence interval of the proportion of smokers in population?
a)
proportion of smokers in the sample phat=52/300=0.1733
b)
σ =sqrt(p(1-p))=0.3785
c)
margin of error E= CONFIDENCE.T(0.05,0.3785,300) =0.043
d)
95% confidence interval of the proportion of smokers in population = phat -/+E =0.173-/+ 0.043 =0.130 to 0.216
22. In a sample of 300 adults, 52 smoke. (22.a) Calculate the proportion of smokers in...
10) In a random sample of 450 people aged 20-24, 22% were smokers, random sample of 400 people aged 25-29, 16% were smokers. a) (4 points) When constructing a confidence interval for the difference between the population proportions of smokers, what must be true in order for the standard normal distribution to be used as an approximation? Show your work please b) (3 points) Construct a 95% confidence interval for the difference between the population proportions of c) (3 points)...
Question 9 20 pts Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 95% confidence; n = 396 x = 48 Question 10 20 pts Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Of 150 adults selected randomly from one town, 30...
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The Centers for Disease Control reported the percentage of people 18 years of age and older who smoke (CDC website, December 14, 2014). Suppose that a study designed to collect new data on smokers and nonsmokers uses a preliminary estimate of the proportion who smoke of 26. a. How large a sample should be taken to estimate the proportion of smokers in the population with a margin of error of .02 (to the...
1) According to the national center on health statistics (2004), 22.4% of adults are smokers. A random sample of 100 adults is obtained. State the criteria for normality and determine if it has been met in this case. (2pts) by Find the mean and standard error for the sampling distribution of sample proportions (2pts) In a random sample of 100 adults, what is the probability that at most 15 of them are smokers? (4pts) What is the probability of getting...
Suppose a sample of 292 Americans over 41 is drawn. Of these people, 52 smoke. Using the data, construct the 80% confidence interval for the population proportion of Americans over 41 who smoke. Round your answers to three decimal places.
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Is college worth it? Among a simple random sample of 350 American adults who do not have a four-year college degree and are not currently enrolled in school, 168 said they decided not to go to college because they could not afford school. 1. Calculate a 95% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it, and interpret the interval in context. Round to 4 decimal places. ( , ) 2....
Is college worth it? Among a simple random sample of 338 American adults who do not have a four-year college degree and are not currently enrolled in school, 156 said they decided not to go to college because they could not afford school. 1. Calculate a 95% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it, and interpret the interval in context. Round to 4 decimal places. (, ) 2....
Is college worth it? Among a simple random sample of 342 American adults who do not have a four-year college degree and are not currently enrolled in school, 158 said they decided not to go to college because they could not afford school. 1. Calculate a 95% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it, and interpret the interval in context. Round to 4 decimal places. ( , ) 2....
A medical researcher says that less than 25% of American adults are smokers. In a random sample of 200 adults, 28.5% say that they are smokers. At a=0.01, do you have enough evidence to reject the researcher’s claim?a. State the null and alternative hypotheses.b. State the Type I and Type II errors.c. Find the critical value. Do you have enough evidence to reject the manufacturer’s claim?d. Construct a 95% confidence interval for the difference of population means.