Question

Plz answer 5 and 6, ASAP

Thank you

5. A square capacitor of area, A 100 cm2 and d 0.1 mm is charged to 200 volts. Determine (a) the value of the capacitor, (b) the charge Q, on the capacitor, (c) energy stored on the capacitor 6. A wire 20 m in length has a resistance of 10 ohm. If the wire's 1.68 x 10-8 ohm-m, what is the wire's cross sectional resistivity is ρ area?

Answer 1

Capacitance of a capacitor C = epsilon_0 A/d A is the are of square plate A = 100 m^2 and plate separation d = 0.1 mm epsilon_o = 8.854 times 10^- 12 C^2/N m^2 substituting all the know values gives C = 8.854e - 06 F b) V = 200 V change on capacitor = Q = CV = 10.001771C1 we plug the values in hand while using the relation give us c) energy stored in capacitor = U = 1/2 CV^2 = 10.1771 J 6) Resistance of a wire of length L = 20 m and area of Cross section A R = rho L/A: rho is the resistivity = 1.68e - 8 Ohm. m and area of cross section = A R = 10.00 Ohm rightarrow A = rho L/R = 3.360e- 08 m^2