Question

For the following reaction:

2NOCl(g) → 2NO(g) + Cl₂(g)

     determine:

     a) the differential rate law

     b) the integrated rate law

c) the value for the rate constant

d) the concentration of NOCl(g) remaining after 275 s in each trial

given:

Trial	[NOCl]0 (mol/L)	Initial Rate (mol/L•s)
1	3.15	7.88 × 10–3
2	6.30	1.57 × 10–2
3	12.6	3.15 × 10–2

Answer 1

- rale = a let the differential rate law will be a Pove = K[noci]. Now rato a when [roci] = 3:15, r= 788x10-3 sv 7.88810-3 = K (3:15) - @ Agan Whe [Noct] ea 6.30 , rel574102 1-57x02 - x(890) 0 © +0 of the years 2 2x = x=1 K[noci). | so, I rate = "Integreled rite will be d[Noci] = K[Nocl] [NOCDE at 'd [noce] [roceš anket 7 [nocit -kt [roci?? [ln [Noci]

Nowy ra 7189 x10-3 [nvei] = 3.15 Ké "/{nect] 7.88810-3 mothest - 2 3:15 boll = 2.5 X10-35-