Question

calculate the theoretical yield of benzoic acid. Given 0.24 g magnesium, 1.00 mL bromobenzene, and 5 g CO2 (dry ice). You must first determine which is the limiting reagent.

Answer 1

C6Hg cooh = Benzoic acid mg = 0.249. Ph-Br= Bromo benzene = 1 ml; drsity of Bromo benzene. = 1059/ml Phabra 1.5 gm. con = 5 gm. moles of mg = 0.24 = 0.01 moles, 1.5 = moles of PhaBr= 0.00955 moles. moles of CO2 = 5 = 0.1136 mols. Ph-Br + mg Ph-mg By ex phong :ph-Br is limiting reagent: moles of Phong Br formed = 0.00955 moles. Phng Br + Co, Hot Ph cooh limiting reagent is Phng By so moles of benzoic acid is = 0.00955 mass of benzoic acid= 0.00955X 122 an. = .165 m