Calculate the equilibrium constant (K) for the following reaction under standard conditions: MnO4 - + 8 H + + 5 Fe2+ → Mn2+ + 4 H2O + 5 Fe3+

Calculate the equilibrium constant (K) for the following reaction under standard conditions: MnO4 - + 8...
4. Calculate the cell potential for the half cells Fe3+/Fe2+ and MnO4- /Mn2+, where the Mn process occurs at the cathode, under the following conditions and predict whether the reaction is spontaneous: [Fe3+] = 1.0 M, [Fe2+] = 0.1 M, [MnO4 - ] = 0.01 M [Mn2+] = 1 x 10-4 M [H+ ] = 1 x 10-3 M Fe3+ + e− → Fe2+ +0.700 V MnO4 − (aq) + 8 H+ (aq)+ 5e− → Mn2+ (aq) + 4 H2O(l)...
Calculate Ecell (the reduction potential for the balanced chemical equation under nonstandard conditions) for the electrochemical cell shown below: Pt | Fe2+ (4.25x10-3 M), Fe3+ (1.50x10-3 M) || MnO4 - (6.50x10-3 M), Mn2+ (2.00x10-2 M), H+ (0.100 M) | Pt. Use the following standard reduction potentials for each half reaction. The Eo for Fe3+/Fe2+ = 0.77 V and Eo for MnO4 - /Mn2+ = 1.51 V.
Calculate the equilibrium constant under normal conditions of the reaction: Fe3+ + Cu+ ⇄ Fe2+ + Cu2+ DATA: Fe3+ / Fe2+ = 0.714V; Cu2+ / Cu+ = 0.158V
What is the expected standard cell potential for the following unbalanced reaction under basic conditions? MnO4-(aq) + Fe+2(aq) ⟶ Fe+3 (aq) + MnO2(s) Given: Fe3+ + e− ⟶ Fe2+ E1/2= 0.771 MnO4−+ 2 H2O + 3e− ⟶ MnO2 + 4OH− E1/2 = 0.558 A. -0.213 V B. +0.213 V C. -1.329 V D. +1.329 V E. None of the above
Using std. electrode potentials listed, calculate the equilibrium constant at 25 ⁰C for the following reaction: O2 (g) + 4 H+ (aq) + 4 Fe2+ (aq) → 4 Fe3+ (aq) + 2 H2O (l) Fe3+ + e- = Fe2+ Ered= 0.77 O2 + 4H+ + 4e- = 2 H20 Ered= 1.23
4. Balance following stoichiometric reaction (a) KMnO4 + FeSO4 + H2SO4 → Fe2(SO4)3 + K2SO4 + MnSO4 + H20 (b) MnO4 + Fe2+ +H - Fe3+ + Mn2+ + H2O
Question 31 4 pts 31. Determine which is reduced agent? MnO4 (aq) +5Fe2(aq) + 8 H(aq) 5 Fe(aq) + Mn2 (aq) + 4H2O(1) Mn in MnO4- H: Fe3+ Fe2+ Question 30 30. Calculate pH of 0.100 M HNO2(aq). K-2.8 x 10-5 9.01 6.21 2.78 5.21
When the following reaction is balanced under basic conditions, what is the ratio of the coefficients of Mn(OH)2(s) to MnO4--(aq)? Mn(OH)2(s) + MnO4 (aq) + MnO42-(aq) (A) 3:1 (B) 1:3 (C) 1:4 (D) 1:5 What is the standard reduction potential for the reduction of permanganate ion to managanese dioxide in acidic solution? Half-Reaction E. V MnO4 (aq) + 8 H(aq) + 5 € → Mn²+ (aq) + +1.51 4 H2O(1) MnO2(s) + 4 H (aq) + 2 e → Mn2+(aq)...
Use standard reduction potentials to calculate ΔG° for the reaction: 2 MnO4- + 10 Cl- + 16 H3O+ →2 Mn2+ + 5 Cl2 + 24 H2O E°MnO4-/Mn2+, H3O+ = +1.507, E°Cl2/Cl- = +1.35827
Calculate the change in Gibbs free energy at standard conditions (TSS) and the equilibrium constant for each of the following reactions. (a) CH4(g) + H2O(g) equilibrium reaction arrow CO(g) + 3 H2(g); ?H° = +205.9 kJ, ?S° = +214.7 J/K ?G° 141.9 Correct: Your answer is correct. kJ K (b) CaCO3(s) equilibrium reaction arrow CaO(s) + CO2(g); ?H° = +179.2 kJ, ?S° = +160.2 J/K ?G° 131.5 Correct: Your answer is correct. kJ K