Molar mass of NaNO3 = 84.9947 g/mol
mass required = (Molarity x molar mass) x (volume in mL / 10000
mass required = (0.25 M x 84.9947 g/mol) x (500 mL / 1000) = 10.6243375 g
grams of the salt should weigh out = 10.6 g

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