At first we number the individuals serially, in a suitable order, from 1 to 80. Since 80 is two digit number, we consider random numbers in sets of two and assign 01,02,...,80 to the individuals with serial number 1,2,...,80 and the remaining i.e. 00, and the numbers greater than 80 are rejected. Random numbers in sets of two are noted, starting from the left end of row 29 and proceeding row wise (we may proceed column wise also). Suppose the are 33, 18, 02, 20, 36, 11, 98, 87, 46. The following table shows the selection of the sample:
Note: If you use random sampling without replacement and a random number comes more than one then select the first and ignore the other repetitions. However this is not required for sampling with replacement.
Please Answer Number 2 2. From a group of 80 individuals, a random sample of size...
In a simple random sample of size 65, there were 37 individuals in the category of interest. Part: 0 / 4 Part 1 of 4 (a) Compute the sample proportion P. Round the answer to at least three decimal places. The sample proportion is Х 5 Part 2 of 4 (b) Are the assumptions for a hypothesis test satisfied? Explain. Yes the number of individuals in each category is smaller than 10. Part: 2/4 Part 3 of 4 (C) It...
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11.* A random sample of size n 64 is drawn from a population with mean μ and standard deviation σ. The mean and standard deviation of the sample are X = 308.9 and s 31.9 a. Find a 90%confidence interval for the mean μ. Interpret this interval. b. Find a 95%confidence interval for the mean μ. Interpret this interval. c. Find a 99%confidence interval for the mean μ. Interpret this interval. d. Compare the widths of...
From the following labeled listing of individuals and the following excerpt from the random digits table B, select a simple random sample of size three. Circle the selected individuals. 3. 10. Stone 07. Smith LISTING: 01. Evenson 04. Jones 02. Buchanan 05. Hazan 06. Woods 11. Vigil 12. Morrison 08. Sanchez 09. Lin 03. Garcia EXCERPT: 21065 44902 37793 11384 20021 07498 06912 12009 45287 71753
From the following labeled listing of individuals and the following excerpt from the random...
Here is an example with steps you can follow: sample size n=9, sample mean=80, sample standard deviation s=25 (population standard deviation is not known) Estimate confidence interval for population mean with confidence level 90%. Confidence Interval = Sample Mean ± Margin of Error Margin of Error = (t-value)×s/√n t-value should be taken from Appendix Table IV. For n=9 df=n-1=9-1=8 For Confidence Level 90% a = 1 - 0.90 = 0.10, a/2 = 0.10/2 = 0.05 So, we are looking for...
In a simple random sample of size 51, taken from a population, 24 of the individuals met a specified criteria. a) What is the margin of error for a 90% confidence interval for p, the population proportion? Round your response to at least 4 decimal places. Number b) What is the margin of error for a 95% confidence interval for p? Round your response to at least 4 decimal places. Number NOTE: These margin of errors are greater than .10...
The number of successes and the sample size for a simple random sample from a population are given below. X-7, 6-35. H:p=0.4, H:p<0.42-001 a. Determine the sample proportion b. Decide whether using the one-proportion z test is appropriate c. If appropriate, use the one-proportion z test to perform the specified hypothesis test. Click here to view a table of areas under the standard normal curve for negative values of z. c. Determine the test statistic, if appropriate Select the correct...
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 109, and the sample standard deviation, s, is found to be 10 (a) Construct a 98% confidence interval about if the sample size, n, is 29. (b) Construct a 98% confidence interval about if the sample size, n, is 13. (c) Construct an 80% confidence interval about if the sample size, n, is 29. (d) Could...
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, X, is found to be 110, and the sample standard deviation, s, is found to be 10 (a) Construct an 80% confidence interval about p if the sample size, n, is 14 (b) Construct an 80% confidence interval about if the sample size, n, is 18. (c) Construct a 98% confidence interval about if the sample size, n, is 14. (d)...
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A simple random sample of size n=20 is drawn from a population that is normally distributed. The sample mean is found to be x = 59 and the sample standard deviation is found to be S = 11. Construct a 95% confidence interval about the population mean. The lower bound is . The upper bound is . (Round to two decimal places as needed.)
The following shows the number of individuals in a random sample of 300 adults who indicated they support the new tax proposal. Political Party Support Democrats 100 Republicans 120 Independents 80 We are interested in determining whether the opinions of the individuals of the three groups are uniformly distributed. If the opinions of the individuals of the three groups are uniformly distributed, the expected frequency for each group is _____ 0.333 0.50 50 None Refer to question 1. The calculated...