Question

Give IUPAC names for the following compounds: HC=CCH=CHC=CH (a) HCECCH=CHCH=CH2 Submit Answer Try Another Version 9 Item attempts remainin

Answer 1

(a) 6 5 4 3 2 1 HC SC-HC=CH-CECH Hex-3-ene-1,5-diyne => Longest chain contains 6 carbons, so Hex => At 1st and 5th carbon it has triple bond, so 1,5-diyne => It has C=C double bond at 3rd carbon, so 3-ene. => Overall the IUPAC name is Hex-3-ene-1,5-diyne (b) 6 HC S 5 C - 4 HC= 3 CH- 2 C= 1 CH2 Hexa-1,3-dien-5-yne (or) 1,3-hexadien-5-yne => Longest chain contains 6 carbons, so Hexa =>If both double and triple bonds are present, the lowest number is given to double bond. => It has C=C double bond at 1st and 3rd carbon, so 1,3-diene. => At 5th carbon it has triple bond, so 5-yne => Overall the IUPAC name is Hexa-1,3-dien-5-yne