Question

Quadratic equation solution Due in 21 hours, 29 minutes x2 (3.3) x (-67) 0 What are the two roots of this equations? Submit Answer Tries 0/10

Answer 1

Compare the given equation by

$ax^{2}+bx+c=0$

Therefore

a=1 ,b=3.3 ,c=-67

Therefore roots are

$X=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

$X=\frac{-3.3\pm \sqrt{3.3^{2}-4(1)(-67)}}{2(1)}=\frac{-3.3\pm 16.7}{2}$

Therefore

$X_{1}=\frac{-3.3+ 16.7}{2}=6.7$

$X_{2}=\frac{-3.3-16.7}{2}=-10$

Therefore answers are 6.7 and -10