Question

Part A When species combine to produce a coordination complex, the equilibrium constant for the reaction is called is the formation constant, K. For example, the iron(W) lon, Fe2+, can combine with the cyanide lon, CN, to form the complex Fe(CN)/ according to the equation Fe+ (aq) + 6CN- (aq) - [Fe(CN) (aq) where K 4.21 x 104 This reaction is what makes cyanide so toxic to human beings and other animals. The cyanide lon binds to the Iron that red blood cells use to carry oxygen around the body, thus interfering with the blood's ability to deliver Oxygen to the tissues. It is this toxicity that has made the use of cyanide in gold mining controversial. Most states now ban the use of cyanide in teaching gold out of low-grade The average human body contains 5.60 L of blood with a Feat concentration of 2.90x10-5 M. If a person ingests 12.0 mL of 200 m M NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide lon? Express the percentage numerically. View Available Hint(s) AED Om? 148 Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining

Answer 1

Volume of blood 152 -5 2.90 X10 concentration of Fe2+ = M - 2+ Molaritu nom ber moles Fe . : Volume g blood -5 2.90x10 - n - number moles = 2.90*10 . . of Fe2+ = 14.5x10 moles Given, 12 ml of 20.0 mM NACN = 1281032 x 20 x108m of Nach - 5 noles - 240 X 10 240 X10 moles of NaCN - 24X10 moi F (Fe CCNPJ cand Given Balanced eaulation Fe2+ (aa) +.6 € (aa) mole daho . Given moles 14.5710 24x10 Feat geautes 6 moles 1 cyanide por one mole moles og Felt Begueres 24x16 moles oy cyanideicns 124x165x1 l, ixco moles op Feat.90" blood. Number of moles of $ét in blood sequestered by cyanide pon : 4x10? mole's percentage go blood sequestered - 4x10° x100 14.5x105 of blood - 27.58 %