(5) Initial speed of the car = 90 km/hour
Convert this in m/sec.
90 km/hour = (90 x 1000) / (60 x 60) = 25.0 m/s
Suppose, u = 25.0 m/s
When the car stops, its speed = 0
Suppose, v = 0
Time taken by the car to come at stop, t = 0.5 min = 0.5 x 60 = 30.0 s
Suppose, a = acceleration of the car
Use the expression –
v = u + a*t
put the values-
0 = 25.0 m/s + a*30.0 s
=> a = -25.0 / 30 = -0.83 m/s^2
So, acceleration of the car = 0.83 m/s^2.
The negative sign of acceleration shows that the car is slowing down.
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