Question

37.22 mL of 0.150 M NaOH is required to completely neutralize a 17.25 ml. sample of phosphoric acid 29 HaPOi (aq) 3 NaOH(aq) - NasPO(aq) 3 H:OU) What is the molarity of this acid?

Answer 1

moles = concentration (M) X volumell) milimoles (mmol) - concentration (M) X volume (ml) volume of NaOH = 37.22 mL concentration of NaOH = 0.150 M mmol of NavH = 0.150 M X 37.22mL = 5.583 mmol. volume of HapOy sample = 17.25 ml H3PO4 (aq) + 3N00H (og) - Na3PO4 loql + 3H₂011) 3 moles of NaOH is required to neutralize I mole of H3PO4 3 mmol of NooH is required to neutralize Immol of H3PO4 = 5.583 mmol of Naot is required to neutralize mmol of H3PO. = Immol X 5.583 mol 3 mmol = 1.861 mmol mmol of H3PO4 = 1.861 mmol concentration of Holly = 0.109 M 1.861 mmol 17.25ml Hence, the molarity of this and is 0.1099 Please Rate