Question

9:08 LTE Question 18 of 23 Submit How many milliliters of Co gas would be produced by the complete reaction of 2.40g of Cat STP according to the following reaction? Remember 1 mol of an ideal gas has a volume of 22.4 L at STP C(s) + H2O(g) → CO(g) + H2(g) STARTING AMOUNT ADD FACTOR ANSWER 4.48 8.92 g/mol có mL CO 22.4 4480 molc 1920 mol CO 0.001 2.40 LCO 28.01 1000 gCO 6.022 x 1023 gC 12.01 g/mol C Tap here or pull up for additional resources

Answer 1

C(s) + H2O(g) -------------> CO(g) + H2(g)

1 mole of C react with steam to gives 1 mole of CO

12g of C react with steam to gives 22.4L of CO

12g of C react with steam to gives 22400ml of CO

2.40g of C react with steam to gives = 22400*2.40/12   = 4480ml of CO >>>>answer