Given x-bar = 3.62 and s = 1.72 and n = 400
Give a 95% Confidence-Interval.
solution:-
given that mean x = 3.62 , standard deviation s = 1.72
and n = 400
95% confidence for z is 1.96
confidence interval formula
=> x +/- z * s/sqrt(n)
=> 3.62 +/- 1.96 * 1.72/sqrt(400)
=> 3.62 +/- 0.1686
=> (3.4514 , 3.7886) four decimal places rounded
Given x-bar = 3.62 and s = 1.72 and n = 400 Give a 95% Confidence-Interval.
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