Question

A car is initiallv at rest on a straiaht road. The araph shows the acceleration of the car along that road as a function of time. -1 -2 -3 0 1 2 3 45 6 7 89 10 11 12 13 14 t(s) What is the speed of the car at t-6 s? 6.0 m/s Your receipt no. is 155-6922 Previous Trles What distance does the car cover in the first 9 seconds? ue A Incorrect. Tries 9/12 Previous Tries What is the speed of the car at t 12 s? You are correct. 0 m/s You are correct. Your receipt no. is 155-6093Previous ries Determine the distance covered by the car between t-11 s and t-13 s? ne Incorrect. Tries 4/12 Previous Tries

Answer 1

The corressponding velocity time graph is as shown below

distance will be the area under velocity time curve.

Distance covered in first 9 seconds = area of ABJ +BCLJ + CDML + DEOM + EFSO + FGRS

= 1/2(1x2) + 1/2(2x(2+8)) + 1x8 + 1/2(2x(8+4) + 1/2(1x(4+7) + 1/2(1x(7+9)

= 1+10+8+12+5.5+8

=44.5m

Distance covered between 11s and 13s = area of HIUT

= 2x7

=14m