Question

10 pts. Castella Ammonia is similar to baking powder giving cookies a crispness found in such Greek specialties as Koulourakia, springerle and gingerbread cookies. What is the equilibrium concentration of Ammonia, NH, for a .100 M NH, solution if the pH of the solution is = 11.6276? Question 9 10 pts. Mixing Clorox and Ammonia results in the formation of NHClO and enough toxic chemicals to cause the (if you'll pardon a politically incorrect old phrase...) "Housewife's Heart Attack". Calculate the pH of .750 M Ammonium Hypochlorite, NH CIO. ka NH* = 5.6 x 10", ka CIO = 2.9 x 10 ANH3 +OH NHy + HOH 750M Sperale fx ty E TT 7500 .750 xx =4.200ooooox 10 3.640 Ka= 5.68100 x² 17:20000000X 10-10 750- x [0+76.480748698 por=-log, a pont 325.669116053 14-5.669116053= 8.330803947 18.33 basic! I

Answer 1

Here is the Solution:

#What is the equilibrium concentration of ammonia, NHz for a 0.100 M NH 3 solection if the pH of the solution is = 11. 6276 - In the aqueous solution, the ammonia NH3 act as a base It accepts hydrogen ions from H2O to yield ammonium (NHA) and hydroxide iou (OH), NH3 (99) + H2OU NH4+ (aq) + Or (aq). The base equilibrium expression will be: Ab= (NH4t] [or] (NH3] Given concentration of NH3 is 0.100 M (mol). and pH = 11. 6276 So, pOH = 14-pH pOH = 14-11.6276 pOH = 2.3724 And then , [OH-] = 10-port [OH) = 10- 2.3724 .[OH) = 4.2423 x 10-3 mol •[NHH] = 4.2423x 10-3 mol • (NH3) = 0.100 – 42423 X10-3= 0.09576 met Hence, equilibrium concentration will be K6= [NH4t] [ort] (4.242310 3x (4.2423x10-3) (NH3 0.09576 = 1.87939 x 10-4 M 1.88 x 10-4M

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