Question

Calculate the moles of C2H6O in 5.66x1024 molecules of C2H6O. Calculate each of the following quantities in 1.50 moles H3PO4: moles of H, moles of O, atoms of P, atoms of O

Answer 1

The solution is given below.

No. of particles Number of moles = 6:02 x 1023 No. of particles = 5.66 * 184 No. of males of 2400 = 5.66 *1024 6.02 X1023 = 0.94 x 184-23 = oigh x 10² = 9:4 moles 1 mole of H₂ Poy contains (a 3 moles of H (6) 1 mole of P (c) 4 moles of o : 1.5 mole of H₃PO4 will contains (a) 3X1.5 moles gH 1. = His motes of H (6] 1x15 moles of P - 1.5 moles ge (0) 4x15 moles go - 6.0 moles go 1 mol of H contains 6-02 x10's atoms 4.5 mole of it will contain = 45 X6-02 X2023 R = 27.09 X1023 atoms I mole of P contains 6.02 xif atoms 1-5 more of p will contain = 1.5x6.02 x1023 =9.03 x 1023 atoms 1 mole go contains 6.02 X10 atoms to moles of 0 will contain = 6 x 6.02 x 10²3. = 36:12 x103 storey