You want to prepare 1.0 L of a 0.15 M NaCl solution in DI water. Show...
Homework Answers
Solution= Molecular weight of NaCl is 58.44 g/mol. This means that 1 mol of NaCl contain 58.44 g in 1litre of the solution. Now calculate for 0.15 M NaCl .
1000ml of 1M NaCl contains = 58.44 g
1000ml of 0.15 NaCl contains = 58.44/0.15 g
= 389.6 g
Therefore 389.6 g of solid crystal NaCl is added in 1L deionised water to make 0.15 M of NaCl in 1L.
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