Question

disregard what i wrote in blue

Starting from rest, a truck drags a 1625. kg crate 120. m up a 5.50º incline with a constant force of 6.25 kN directed parallel to the plane. The friction coefficient between the sled and surface is pk = 0.375. 6,25 base 6250 W TERSKE 120m 5.50 a) Calculate the work done on the crate by the truck. b) Calculate the work done on the crate by the normal force. c) Calculate the work done on the crate by gravity. d) Calculate the work done on the crate by friction. e) Use the Work-Energy Theorem to calculate the speed of the crate after 160 m. W=F.O

Answer 1

0 - 5.50 mass of orase m = 1625kg displacement d = 120m force on crose by bucks, F = 6.25 kN F = 8.254103 ex = 0.375 @ work done by druck ear.d = 0, 25x103 x 120 = 7.50X105)

Normal N = mg cose cwork done by normal = of mgfino ng mgcoso Because, normal force is perpendicular to displa camere о Ско - © work done by gravity - - Mganood = - 162579.8* sin(5:50) +120 -1.834)05J ł fk = ex. N = ex. mg coso Work done by friedon = - Skod an elk.mg cosoid = -0.375 4 182549.8 xcos (5.50) X120 = -7.134105)