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1 M Sucrose Solution (Sucrose = C12H22011) Formula Weight of Sucrose_342 g/mol How much sucrose would you need to make 1 L of
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Answer #1

Given that the formula weight or molecular weight of sucrose (C_{12}H_{22}O_{11}) is 342 g/mol.

Hence, 1 mol of sucrose is equivalent to 342 g of sucrose.

1 M solution of sucrose contains 1 mol of sucrose per litre of solution. i.e 1 M = 1 mol/L

Hence, amount of sucrose needed to make 1 L of 1 M sucrose is

\frac{1 \ mol}{1 \ L} \times \frac{342 \ g}{1 \ mol} \times 1\ L= 342 \ g

Hence, we need 342 g of sucrose to make 1 L of 1 M sucrose.

Similarly, to make 100 mL(=0.100 L) of 1 M solution,

\frac{1 \ mol}{1 \ L} \times \frac{342 \ g}{1 \ mol} \times 0.100 \ L= 34.2 \ g

Hence, we need 34.2 g of sucrose to make 100 mL of 1 M sucrose solution.

Similarly, to make 50 mL(0.050 L) of 1 M sucrose solution

\frac{1 \ mol}{1 \ L} \times \frac{342 \ g}{1 \ mol} \times 0.050 \ L= 17.1 \ g

Hence, we need 17.1 g of sucrose to make 50 mL of 1 M sucrose solution.

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