Question

The rms speed of molecules in a gas at 27°C is to be increased by 3%. To what temperature (in °C) must it be raised?

Answer 1

The expression for rms velocity of the gas molecules is, 3KT 775 1 = The rms velocity, is directly proportional to the root of the temperature. The relation between rms velocity and the temperature. V2 VT2 The final rms velocity is, v2 = V+3%v; = v(1.03) The final temperature of the gas is, _(v; (1.03)) (300 K) = 318.27 K = 45.27° C