Homework Answers
mmoles of NaOH = 10.0 x 0.287 = 2.87
mmoles of HNO3 = 31.6 x 0.11 = 3.476
[H+] > [OH-]
[H+] = 3.476 - 2.87 / (10.0 + 31.6)
= 0.0146 M
pH = -log[H+]
= -log (0.0146)
= 1.84
pH = 1.84
answer : C) 1.84
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