Question

Write a balanced nuclear equation for the decay of radon-222 to polonium-218.

Answer 1

222 Balanced nuclear equation for decay of radon -222 to polonium- 218 222 8 Rn 2 Po + 4 He - RodonRn produces 2 po by alpha decay, in which atomic number is reduced to a un mass no. reduces to 4 units. 222) mass no. 4 unit 218. mi Rn 218 Po & alpha Decay (4e) atomic number is reduced to a unit & nedlecules (86) noo g unit Iodine-123 Brody ces tellurium 123 affer I election capture. Answer → Abruc number reduced to single unit, while mass number remains same. e of 125 I te 23 Te 123 Te & Phosphorons 28 to silicon-28 observed in Watupe It produces position emmission Answer +As phosphorous light it undergo emmission position) 28 P 285, the In which the atomic number decrease to one uni