Question

7. If a photon absorbed 6.043 x 10 J of energy, what is the wavelength of this photon? 8. What part on the electromagnetic spectrum does the wavelength calculated in question 7 fall in (Refer to Figure 2)

Answer 1

Step 1: Explanation

We know,

E= hv where, h = planck's constant = 6.626 × 10^-34 J-s

frequency (v) = C/λ

and C = 3 × 10⁸ m/s =speed of light

so the equation becomes

or, E= hv

or,  λ = hc / E

(7) Step 2: Calculation of wavelength

Given, E = 6.043 10^-24 J

by substituting the value in  the above equation

λ = hc / E = ( 6.626 × 10^-34 J-s × 3 × 10⁸ m/s ) /   6.043 × 10^-24 J = 3.29 × 10^-2 m

(8) Step 3: Identification electromagnetic spectrum region

the calculated wavelength lies in the microwaves region

[ because from the electromagnetic spectrum we know microwave region lies from 10^-1 m to 10^-3 m ]