Question

4. Use the velocity versus time v() graph below to answer the following questions: 20 m/s 10 m/s 10 s 20 s 30 s -10 m/sL a. What is the displacement between 0-10 seconds? b. What is the displacement between 0-35 seconds? c. What is the acceleration at t- 10 seconds?

Answer 1

as the curve is uniform, so acceleration of the curve is given by

a = ( 0 - 20) / ( 20-0) = - 1 m/s^2

now applying 2nd equation of motion

v^2 = u^2 + 2 a d

10^2 = 20^2 - 2 * 1*d

d = 150 m

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b)

displacement = area under v-t curve

d = 0.5* 20* 20 + (-10)*10

d = 100 m

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c)

a = - 1 m/s^2

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