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3) Ch 13 - The quartz crystal in a digital watch has a frequency of 32.8 kHz. What is its period of oscillation? A) 3.05x10-5
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Answer #1

* We have of frequency, f = 32-8 kH2 => 39.8 x103 HZ Time period of oscillation is, T= If s2/32.87103 * 3.050105s 1.71 3.05x

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