#1.
Below are the null and alternative Hypothesis,
Null Hypothesis: μ = 93.55
Alternative Hypothesis: μ ≠ 93.55
Option A
#2.
In words: Option B
#3.
point estimate is 100.550
#4
Given CI level is 90%, hence α = 1 - 0.9 = 0.1
α/2 = 0.1/2 = 0.05, Zc = Z(α/2) = 1.64
CI = (xbar - Zc * s/sqrt(n) , xbar + Zc * s/sqrt(n))
CI = (100.55 - 1.64 * 18.4/sqrt(80) , 100.55 + 1.64 *
18.4/sqrt(80))
CI = (97.176 , 103.924)
97.176 to 103.924
#5.
Reject the null hypothesis
Suppose that BC financial aid alots a textbook stipend by claiming that the average textbook at...
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claiming that the average textbook at Vesey bookstore cost $80.87.
Do you want to test this claim. The Noel and alternative hypothesis
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Suppose a geologist believes that the average chloride concentration in her local water supply is above the national average of 75 ppm. The geologist defines a null hypothesis, Ho:u = 75 ppm, to reflect the mean chloride concentration in the national water supply. She formulates an alternative hypothesis, H1: u > 75 ppm, to indicate that her locality has a higher concentration of chloride in its water supply, on average. In these hypotheses, y represents the true mean concentration of...
Help with the following problem urget, bellow is the csv
data.
Campus
Online
153.83
148.66
212.21
214.58
191.65
191.24
142.49
141.73
154.71
152.62
223.36
224.79
93.93
92.87
112.21
106.41
182.58
185.15
179.55
177.33
187.51
185.17
168.75
167.08
Assignment 2: Problem 4 Previous Problem Problem List Next Problem (1 point) A professor in the school of business at a certain university wants to investigate the claim that the prices of new textbooks in the campus store are higher than a competing...