Question

QUESTIONS 1. Cornstalks have a C/N ratio of 67/1 with an average 0.7% N by weight. a. How many lbs N are contained in 1 ton of cornstalk residue? b. How many lbs C are contained in 1 ton of cornstalk residue? c. Assuming 67% of the Cin I ton of cornstalk residue goes toward respiration (CO2) and energy production, how many lbs C are used by microorganisms for synthesizing cellular compounds? d. Assuming the C/N ratio of microorganisms (microbial biomass, biomolecules) is 8/1, how many lbs of additional N would need to be added to avoid N. immobilization? many grams of NaOH ( 40

Answer 1

I C/N ratio : 67:1 0.7%.N by weight Ilbs = 6-453592 kg iton = 1000 reg. = 2000 pound Coolbl) Contained in I ton of Cornt telle dessuten @ How many lbs N are 0.7% of Iton a 0.7x 2000 = 14 lbs 6 How man cbs G are Contained a ton of Corn stole svidual 67:1 = C/N = 67 = 2 2 2 2 2 2 62 K14 = 938 lbs C in Cbs = 938 lbs for Iton Assuming 67% of the cinlton ifttred of Cornstale residue goes to ward respiration (CO₂) and energy production how man lbs Care cesed by microorganisms for Synthesiacing celled an component - 67% C » 0.678 938 Lbs = 628.46 (bs iswed for respiration Assuming 9 the CIN ratio of microorganisma (microbial biom ass, biomoleculesd is 8/1, how many (brot additional a would be need to be added to avoid 0-immobilzation C/N 67/1 = requisid = 8/1 938165 C 117.25 Nis required to maintain 8/1 KI

but it has only Remaining to be 14 Lbs & fer added = 117. 25-14 = 101-25 (55. 6. WooH Fhut 90 g/mol [C] = 2.1M) 4 liter for 1 Liter 2.1 moles. for 4 likes 2,1 x 4 = 8.4 moles =8-4440 = 336 grams of Naot 10.3mL OL 2.1M Naoth is initially added. mmolas 10.3 mL xalxrom 2000 ml 91-63 read na ott es added. 17.5mL of 0.69 MHCl 2000 AL X 0.69x10 mmolar a 17.5mb x 0.69*10 mmoles = 12.075 mmoles of Hol is ased for tilsator i mole of anott con Old requise I mole of Hol 12.075 mmoles of OH was remaining > Na Cozt H₂O COqt a NaOH a modes 244-013/mole Imole ago.2mg of CO₂ = 210-2x10 g = 0.004776187 moly 44.00 smole Nach = 2X0.004776182=0.0098smoles -9.55 mmiles

@ I acre fe now slice = 2x106 lbs go grans - 3-cewa aldays = 3/0.2mg = 1 day = 10.0095 mg 2x 106 lbs= 281068 0.453592 kg = 24106 40.45392x103 grams - 0.907874109 gramo CO2 evolved por day 0.90784210 grams x10.0095mg 20 grans 2 454351224 mg = 454351224 ton Hon= 10000g = 106 g = 10 mg = 0.4543 ton of cool is evolled per day RAFINA