Question

ps Using standard rules, assign oxidation numbers to the atom reques The oxidation number of the Catom in C6H40 is The oxidation number of P in Ca3(PO4)2 is The oxidation number of N in N2H403 is (b) (3pts) Using standard rules assign oxidation numbers to the various atoms in the following reaction: 4P4 + 7 S8 ------> 8 P2S- The substance oxidized is The substance reduced is The oxidizing agent is (c) (3pts) Complete the following table by placing the appropriate letter(s) in the space provided. Use S for soluble, I for insoluble, and CBT for can't be determined using solubility rules. S? I? CBT? CuSO4(s) Fe(NO3)3(s) Caz(PO.)2(5)

Answer 1

of oxidation Let it . 0 number of c in Cahyo is. be x 6x + 4 (ON of H) + 1 ON of 0 1 L - 2 6x + 4 (1) – 2=0 6x = -2 x = - 26 [x = -0.33 ON of c. b) Oxidation number of P in Cas (Pou) 3 LON of ca) + 2 (ON of P + 4CON of o)) 3 (2) + 2(x - 8) = 0 6 + 2x - 160 [2=5] . ON of e c) Oridation number of Nin Na Hu Oz is. 2 CON OGN) + 4 ON of H) + 3 CON of o)=0 2(x) + 4(1) + 3(-2) = 0 2x+ 4 - 6 = 0 2x = 2 [x=14 ON of N.