Homework Answers
a)P(classified as defective)=P(defective and classified as defective)+P(not defective and classified as defective)=0.005*0.95+(1-0.005)*0.01=0.01470
b)
P(defective given classified as defective)=P(defective and classified as defective)/P(classified as defective)
=0.005*0.95/0.01470=0.323129
c)
P(classified as non defective)=1-P(defective)=1-0.01470=0.9853
hence P(good given classified as non defective)=P(good and classified as non defective)/P(classified as non defective)
=0.995*0.99/0.9853=0.999746
hence P(good given
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