Homework Answers
Sample
n = 200
Mean = 520
Std Dev = 100
Std Error (SE) = 520/1001/2 = 52
Alpha = 0.05
Null and Alternate Hypothesis
H0: µ = 500
Ha: µ > 500
This is a one-tailed test
Test Statistic
t = (520-500)/52 = 0.385
tCritical = 1.653
p-value = TDIST(0.385,200-1,1) = 0.350
Result
Since the p-value is greater than 0.05, we fail to reject the null hypothesis.
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