If the probability of a student running in track is 0.3, the probability of a student...
If the probability of a student running in track is 0.3, the probability of a student running or long jumping in track is 0.63, and the probability of running and long jumping in track is 0.17, what is the probability of a student long jumping in track?
Homework Answers
Let, ‘A’ be an event that a student running in a track and ‘B’ be an event that a student long jumping in a track.
P(A) = Probability of a student running in a track.
P(B) = Probability of a student long jumping in a track.
P(AUB) = Probability of a student running in a track or long jumping in a track.
P(A ∩ B) = Probability of a student running in a track and long jumping in a track.
We have given,
P(A) = 0.3; P(AUB) = 0.63; P(A ∩ B) = 0.17
We know that P(AUB) = P(A) + P(B) - P(A ∩ B
- 0.63 = 0.3 +P(B) – 0.17
- P(B) = 0.5
Probability of a student running in a long jumping track is 0.5
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