Question

8. Explain why the complex (Fe(H2O) has de = 14,000 cm', while [Fe(H2O) has 3 = 9,350 cm. 9. Suggest a reason why copper'll) compounds are often colored but copper(l) compounds are colorless. 10. Sketch the d-orbital energy-level diagram for a square planar complex Spectrochemical series: COCN' >phen > NOx > en > NH3> NCS > H2O > F>RCOO > OH > CT > Br> 50m 750 nm 400 m Sem 430 nm 190 mm

Answer 1

tog For metal hon in. Low oxidation state metal ion in high oxidation state Higher the charge ont a metal more is the splitting of d'orbitals higher the ao value [Fe(4,0)]3+ here central ometal Fets events [Fe (H₂O)]2+ ere central metal Feet Do [Fe (H₂O) 7 3t has higher 46 value - 14,000 om thom [Fe(HO)] 2+ 4 = 9,350 cm

19) Cu2t has gd electrons. 11/12/1741 so in octahedoal, tetrahedral or square planner or in any geometry. there is a dh d'tronsition of electron is possible - so so cat complexes are 27 often coloured. 3d Cut has 10 ud electrons 12/12/12 12 12 80 in Cut complexes. there is no d d transition of electrons so this compounds or not coloured.

X All the ligands in a square plannen geometry are along X and Y axisin a ng so orbitals, taxing directed along X, Y axis are energitically higher. Charles Splitting of a orbitals. - dresy zobor 3 in square planner "Creometry dry da2 - - drz, dyz