Question

and with minitab please.

3. Perform a hypothesis test for H: Suz vs. H: > M2. The sample sizes are n = 10 and na = 15, sample means are X44.7 and that X2=53.8 and sample standard deviations are si = 11 and s2 = 6. Perform the test assuming variances are unequal. Use 5% significance.

Answer 1

using minitab>stat>basic stat>two sample t test

we have

Two-Sample T-Test and CI

Sample N Mean StDev SE Mean
1 10 44.7 11.0 3.5
2 15 53.80 6.00 1.5

Difference = μ (1) - μ (2)
Estimate for difference: -9.10
95% lower bound for difference: -15.89
T-Test of difference = 0 (vs >): T-Value = -2.39 P-Value = 0.983 DF = 12

since p value is greater than 0.05 so we accapt Ho