Use Gauss' law for this problem. The electric flux through the entire cube is:
now since the charge is at the center and there are 6 faces for a cube, the electric flux through one face of the cube is:
.
Note that this answer is independent of the dimensions of the box.
s d 33% 7:57 PM A webwork.phys.yorku.ca/webwork2/PHYS1010/w 2 of the questions remain unanswered. (1 point) THE...
..d 68% 15:45 PM D webwork.phys.yorku.ca/webwork2/PHYS1010/w (1 point) THE PROBLEM We can create electric charges of about a C by scuffing socks on a carpet or rubbing a balloon on hair. Consider two charges, g 1.2 C and q-2.2 AC, with a distance of d-12 cm between them. Find a location where the electric field is zero. PAPER SOLUTION Solve the problem on paper first, including all four IDEA steps. You will become a better physicist that way Have you...
O webwork.phys.yorku.ca/webwork2/PHYS1010/w (1 point) . THE PROBLEM A laboratory room is filled with a constant electric field which enters through the left wall and exists through the right wall. An empty wooden cube sits on the floor of the lab. The field has magnitude E-1.71 kN/C and the cube has dimensions 1x L × L where L-122 cm. Calculate the electric flux through each of the six sides on the wooden cube when (a) its left side faces the left...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...