Question

Mass Data and Calculations Table Aluminum Brass Iron M1 (kg) | M2(kg) | M3 (kg) | M4 (kg) | M(kg) | ơn--1 (kg) | 때(kg) 0.0863 00864 0.086 0086 0.08631 1.436,10 .18 l0 02699 0.2699 0.26 0.260 0.2696945830 .2810 Zero Reading of the calipers Length Data and Calculations Table 0.0315 0.0314 0035 0.0349 0.00165 8.250" Aluminum 0.0318 10.0318 | 0.0310|0.0316 |0.0318 |1.633x10"18-16 SUP 00315 0.0315 lo'031S 0,0316 0,0315 ч L0824(1014.12(10 Iron Diameter Data and Calculations Table 10.0318. | О-O315010, 03144 |0,03150|0.03244|0.00165|8. 2 Slo Aluminum Brass 8 Iron

Using the tables answer the question 1, (under questions)

Answer 1

1. Consider the uncertainty in the measured value of (_$\rho$) to be given by $\alpha$_$\rho$.

Taking the one decimal place of $\alpha$_$\rho$ as the least significant digit in _$\rho$, how many significant figures are indicated for each of the measurement of '_$\rho$'.

(a) For Aluminium, we have

_$\rho$exp = 2764 kg/m³ = 2.764 x 10³ kg/m³         ;       Significant figure = 4

$\alpha$_$\rho$ = 167 kg/m³ = 1.67 x 10² kg/m³              ;       Significant figure = 3

_$\rho$known = 2700 kg/m³ = 2.70 x 10³ kg/m³       ;       Significant figure = 2

(b) For Brass, we have

_$\rho$exp = 8387 kg/m³ = 8.387 x 10³ kg/m³         ;       Significant figure = 4

$\alpha$_$\rho$ = 86 kg/m³ = 8.6 x 10¹ kg/m³                ;       Significant figure = 2

_$\rho$known = 8400 kg/m³ = 8.4 x 10³ kg/m³       ;      Significant figure = 2

(c) For Iron, we have

_$\rho$exp = 7937 kg/m³ = 7.937 x 10³ kg/m³       ;        Significant figure = 4

$\alpha$_$\rho$ = 22 kg/m³ = 2.2 x 10¹ kg/m³                ;        Significant figure = 2

_$\rho$known = 7850 kg/m³ = 7.85 x 10³ kg/m³       ;        Significant figure = 3